• jjjalljs@ttrpg.network
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    3 days ago

    I’m the kind of guy who will look stuff up. I think it’s really important to admit when you’re wrong and the other person was right. Don’t move goal posts or claim you misunderstood. Just own it.

    Like I was having a debate with my partner about if it was faster to go all the way up and over, or make a lot of turn-right then turn-left. I thought the ladder was faster because it approximates a straight line. She was like no that’s crazy. Eventually I found that’s called Manhattan distance and she was right, and I fully admitted defeat.

    • Septimaeus@infosec.pub
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      3 days ago

      Love this. People who display like trophies the times they were wrong have learned one of life’s simple truths: there are no trophies for being right, just crappy knockoffs of the learning process one forgot.

    • calcopiritus@lemmy.world
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      2 days ago

      I don’t understand your conclusion.

      Yes, Manhattan distance exists, it has a name. But I don’t understand how having a name makes it faster “a straight line distance” also has a name, euclidean distance. And always euclidean ≤ Manhattan.

      So if on both routes you go at the same speed, it is faster to take the one of the euclidean distance.

      • jjjalljs@ttrpg.network
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        2 days ago

        Well, we were literally walking in Manhattan when it came up, and couldn’t take the euclidean straight path. We could only walk on the grid of streets.

        (This is setting aside factors like waiting to cross, or a busier street)

        • calcopiritus@lemmy.world
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          2 days ago

          Ah. I originally missread your original comment.

          Yes, in a grid where the Manhattan distance is the minimum one, taking a single 90° turn is the fastest, since that path will have the length of the Manhattan distance.

          However, it’s not the only path. The “ladder” one you said will be the same length.

          While we are at it, if you wanna search for more. The same flawed assumption of “a ladder approximates a straight line” can also lead to π=2. Since you can enclose a circle in a square (Wich has perimeter 4R), then fold the corners recursively so there is a “stair” along the circle’s perimeter. That “stair” would have a length of 4R, but the circle’s perimeter is 2πR.