Day 7: Laboratories
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
- You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL
FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465


Go
Now I’m behind by 1 day, will try to catch up.
For part 2 I spent a good while thinking about it, then when I convinced myself my plan could work, struggled a bit with the implementation. But it worked in the end. Basically grid[i][j] is how many different ways you can reach a cell. Start at 1 on the S cell, then propagate the values down and keep adding up the nums when you reach cells through different paths. The answer is the sum of the nums in the last row.
spoiler
func part2() { // file, _ := os.Open("sample.txt") file, _ := os.Open("input.txt") defer file.Close() scanner := bufio.NewScanner(file) input := [][]rune{} for scanner.Scan() { line := []rune(scanner.Text()) input = append(input, line) } m := len(input) n := len(input[0]) grid := make([][]int, m) for i := range m { grid[i] = make([]int, n) } for i := range m { for j := range n { c := input[i][j] if i == 0 { if c == 'S' { grid[i][j] = 1 } continue } if c == '^' { grid[i][j-1] += grid[i-1][j] grid[i][j+1] += grid[i-1][j] } else { grid[i][j] = grid[i][j] + grid[i-1][j] } } } paths := 0 for j := range n { paths += grid[m-1][j] } fmt.Println(paths) }