Day 7: Laboratories

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FAQ

  • reboot6675@sopuli.xyz
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    2 days ago

    Go

    Now I’m behind by 1 day, will try to catch up.

    For part 2 I spent a good while thinking about it, then when I convinced myself my plan could work, struggled a bit with the implementation. But it worked in the end. Basically grid[i][j] is how many different ways you can reach a cell. Start at 1 on the S cell, then propagate the values down and keep adding up the nums when you reach cells through different paths. The answer is the sum of the nums in the last row.

    spoiler
    func part2() {
    	// file, _ := os.Open("sample.txt")
    	file, _ := os.Open("input.txt")
    	defer file.Close()
    	scanner := bufio.NewScanner(file)
    
    	input := [][]rune{}
    
    	for scanner.Scan() {
    		line := []rune(scanner.Text())
    		input = append(input, line)
    	}
    
    	m := len(input)
    	n := len(input[0])
    	grid := make([][]int, m)
    	for i := range m {
    		grid[i] = make([]int, n)
    	}
    
    	for i := range m {
    		for j := range n {
    			c := input[i][j]
    			if i == 0 {
    				if c == 'S' {
    					grid[i][j] = 1
    				}
    				continue
    			}
    			if c == '^' {
    				grid[i][j-1] += grid[i-1][j]
    				grid[i][j+1] += grid[i-1][j]
    			} else {
    				grid[i][j] = grid[i][j] + grid[i-1][j]
    			}
    		}
    	}
    
    	paths := 0
    	for j := range n {
    		paths += grid[m-1][j]
    	}
    
    	fmt.Println(paths)
    }